Delete quotation marks from a variable Unix Linux Stack Exchange
I ve got a variable string value which looks like webenv1 value My ion is how can I delete the quotation marks and comma from this variable value to permanently change the value Unix Linux Stack Exchange is a ion and answer site for users of Linux FreeBSD and other Un x like operating systems Re set the variable
Shell Script to remove double quotes within the column value, 30 A very simple option is to use sed as Dani proposes if you want to remove all double quotes echo This is my program Hello World sed s g This is my program Hello World Nevertheless if you want to remove only internal quotes I would suggest removing all quotes and adding one at the beginning and one at the end as follows

Linux Remove double quotes embracing variable strings from terminal
What if I have to remove double quotes only from variables that follow the string from I have other variables embraced by double quotes in the file and I need this kind of replacement only for the first variable after from splunk Remove non duplicate lines in Linux 8
Stripping single and double quotes in a string using bash standard , I m looking for something that will translate a string as follows using only bash standard Linux commands Single quotes surrounding a string should be removed Double quotes surrounding a string should be removed Unquoted strings should remain the same Strings with unmatched surrounding quotes should remain the same

How to remove quotes from text Unix Linux Stack Exchange
How to remove quotes from text Unix Linux Stack Exchange, This uses the gsub command to remove all double quotes from the first field on each line The NR 1 at the end makes sure that the first line is not printed To remove the double quotes from the first field but only if they appear as the first and last character of the field awk F 1 1 substr 1 2 length 1 2

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Bash CLI remove quotes from output of a command
Bash CLI remove quotes from output of a command However I need to assign the output of this variable to a command I tried to do this and this works How do I remove the quotes i e change web to web command line text processing json Share Improve this ion Follow edited Nov 25 2017 at 4 21 muru 196k 53 53 gold badges 482 482 silver badges 737 737 bronze badges
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Unix Linux Stack Exchange is a ion and answer site for users of Linux FreeBSD and other Un x like operating systems I want to parse a variable in my case it s development kit version to make it dot free where apparently the lack of the final forward slash and replacement string are interpreted as delete See here Remove particular characters from a variable using bash. How do I remove everything between and including single quotes in Unix Linux Example Input WHERE EnodeB Fin Date Time Fin 2022 In a regular file As the output of some command In a variable Please edit and be specific Kamil Maciorowski May 18 2022 at 15 22 awk Removing Double Quotes from CSV File Quoted Strings But I would like not having the single quotes on the final invocation of mkvpropedit like so mkvpropedit edit 1 set language eng lish I tried also echoing the array into a variable and echo removes the single quote but then I m not able to use the variable as an argument of mkvpropedit because the single quotes appear again

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