Shell script pass variable in ssh Unix Linux Stack Exchange
Ssh sends that over to sshd which if it accepts it passes it as an environment variable to the login shell of the user which then passes it to that csh command which can then expand it But as mentioned earlier that won t work unless the administrator of the host machine has added a AcceptEnv LC parameter or AcceptEnv LC that one
Linux pass the variable through SSH and run commands using the , 1 Answer Sorted by 1 Add bash to the end of the initial command ssh test sh should look like bin bash execommand ssh hostname application app1 bash EOL echo application cd opts logs application EOL source input txt execommand so that your commands are actually processed by the shell
Linux Using Bash variable in SSH config Stack Overflow
Using Bash variable in SSH config closed Ask ion Asked 8 years 3 months ago Modified 8 years 3 months ago Viewed 7k times 4 Closed This ion does not meet Stack Overflow guidelines It is not currently accepting answers
Create variable over ssh in bash Unix Linux Stack Exchange, Create variable over ssh in bash Ask ion Asked 6 years 4 months ago Modified 6 years 4 months ago Viewed 5k times 1 bin bash x ssh T root jumpbox ssh T root IP EOF YY date y echo YY EOF OUTPUT Trying tunnel from jumpbox
Capturing SSH output as variable in bash script Stack Overflow
Capturing SSH output as variable in bash script Stack Overflow, 47 time command prints result to stderr not to stdout Thus it is not piped into your variable You should reroute stderr to stdout to achieve what you want result ssh host time command 2 1 And your full code can look something like this
How To Use SSH Keys For Authentication Up
How to use command line variable in an SSH command
How to use command line variable in an SSH command Mar 29 2022 at 12 44 so when you ran the since removed ssh o i Host that would have passed b 06 30 20 18 10 e 06 30 20 23 59 c name to the ssh program itself which would have errored out because e is used to set the ssh escape character and 06 30 20 23 59 is not a character for example
Array Bash Use Variable As Name Of Associative Array When Calling
Variables 101 Variables are named symbols that represent either a string or numeric value When you use them in commands and expressions they are treated as if you had typed the value they hold instead of the name of the variable To create a variable you just provide a name and value for it How to Work with Variables in Bash How To Geek. The trick is to double quote the string you feed to eval so that myvar gets substituted with 6 and to backslash the outer dollar sign so that eval gets a string 6 I got user for the output but I tried it on a multi processor RHEL machine Share Improve this answer edited May 15 2019 at 10 55 SebMa 2 059 4 24 41 If you are signing into a terminal session or through SSH and authenticate your shell session will be set as a login shell If you start a new shell session from within your authenticated session like we did by calling the bash command from the terminal a non login shell session is started You were were not asked for your authentication
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