How can I use a regex variable for a find and replace command in bash
1 This is a follow up to a previous ion I had asked For that ion I received an excellent answer by markp fuso demonstrating the use of an array of search patters for sed to perform a particular substitution task
Regex How to replace a pattern in a string in bash Stack Overflow, Regex How to replace a pattern in a string in bash Stack Overflow How to replace a pattern in a string in bash Ask ion Asked 9 years 6 months ago Modified 5 years 6 months ago Viewed 2k times 2 I have the following strings stored in variables in shell a1 aaa bbb3 12 ccc a2 aaa 2 bbb ccc
Bash variable substitution with a regex not working as expected
1 asked Jan 31 2018 at 12 34 Oscar Hierro 1 117 1 10 16 2 Who told you bash supports RegEx with its builtin string substitution iBug Jan 31 2018 at 12 36 iBug but it does as far as I can tell A simpler pattern like MYVAR a z X works Oscar Hierro Jan 31 2018 at 12 53 1 That s not regex
Variable substitution bash VAR search replace and weird regex , Aug 28 2013 at 2 33 Bum that ll be why I had a hunch it may have been the case I was trying to find clarification of the matching mechanism without much success heads off to read about extglob looks like a job for sed Drav Sloan Aug 28 2013 at 2 38 1
Bash Find and replace regex with another string Stack Overflow
Bash Find and replace regex with another string Stack Overflow, 1 I have the following string libVersion 1 23 45 6 and I need to replace 1 23 45 6 with 1 23 45 7 Obviously the version could be any number with similar format it does not have to be 4 numbers I tried to use the following but doesn t work echo libVersion 1 23 45 6 sed s 0 9 1 23 45 7 g regex bash parsing sed Share Follow
Python String replace How To Replace A Character In A String
How to use sed s substitute with a regex pattern as variable
How to use sed s substitute with a regex pattern as variable 1 Answer Sorted by 1 sed s Life temporary Life 1permanent Here 1 refers to the first pair of parentheses in the pattern It s the only pair in this case but in general you can have more pairs and then you can use 2 3 etc up to 9 The parentheses are escaped Without they would be taken literally and 1 wouldn t work
Unix Linux Bash Replace String With Command 2 Solutions YouTube
Bash variable replace first letter with the letter in using string manipulation Ask ion Asked 5 years 10 months ago Modified 5 years 10 months ago Viewed 8k times 2 let s say I have variable string and now would like to replace use brackets for the first letter variable firstletter firstletter Bash variable replace first letter with the letter in using string . Learn how to replace a single or multiple occurrences of a substring inside a string in Bash Sep 24 2021 Avimanyu Bandyopadhyay Replacing a Substring With Another String in Bash Here s the scenario You have a big string and you want to replace part of it with another string 2 Answers Sorted by 6 In the var pattern replacement ksh93 operator pattern is interpreted as a shell wildcard pattern not a regexp In ksh93 you can switch to basic extended or augmented regexps with G E X respectively so you could do var2 var E 0 9 10 tgz For instance Or use its extended glob patterns
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