Bash Remove Quotes From String Variable

4 Ways to Remove or Strip Quotes From String in Bash With Cases

In Bash whether the quotes are at the beginning or at the end or even within the string you can utilize the parameter expansion in a concise format to remove both single and double quotes from strings Case 1 Removing Double Quotes From String Using Parameter Expansion in Bash

Stripping single and double quotes in a string using bash standard , 24 I m looking for something that will translate a string as follows using only bash standard Linux commands Single quotes surrounding a string should be removed Double quotes surrounding a string should be removed Unquoted strings should remain the same Strings with unmatched surrounding quotes should remain the same

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Delete quotation marks from a variable Unix Linux Stack Exchange

I ve got a variable string value which looks like webenv1 value My ion is how can I delete the quotation marks and comma from this variable value to permanently change the value And to remove both quotes and comma webenv1 webenv1 Delete everything before last slash in bash variable 1

Remove particular characters from a variable using bash, Remove particular characters from a variable using bash Ask ion Asked 10 years ago Modified 1 year 1 month ago Viewed 623k times 220 I want to parse a variable in my case it s development kit version to make it dot free If version 2 3 3 desired output is 233

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How do I use a Bash variable string containing quotes in a command

How do I use a Bash variable string containing quotes in a command , Short answer see BashFAQ 50 I m trying to put a command in a variable but the complex cases always fail Long answer Putting commands or parts of commands into variables and then getting them back out intact is complicated When the shell expands a variable on the command line if the variable was in double quotes it s not parsed if

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Empty Quotes Assigned To Variable Explanation solved The

Remove specific word in variable Unix Linux Stack Exchange

Remove specific word in variable Unix Linux Stack Exchange 4 Answers Sorted by 62 Using bash substring replacement FOO FOO WORDTOREMOVE The replaces all occurences of the substring WORDTOREMOVE with the content between and In this case nothing For information on this and other ways to work with strings in bash see the section 10 1

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Remove Last Character From A String In Bash Delft Stack

How To Add Double Quotes Around Java Object And String Variable

8 One of the changes between bash 4 3 alpha and the previous version bash 4 2 release When using the pattern substitution word expansion bash now runs the replacement string through quote removal since it allows quotes in that string to act as escape characters Bash Replace single quote by two quotes in string. 1 Just to make sure are you trying to 1 remove the first line and 2 remove double quotes from fields on any other lines Can double quotes appear anywhere else than the first field And should they only be removed from the first field as your ion s title suggests if they do fra san May 21 2020 at 11 21 1 Thank you fra san Bash Remove Quotes from String Bash Add Quotes to String Bash String Concatenation Bash String Substitution Bash String Variables Bash String Operations Bash String Comparison How to Extract a Substring in Bash How to Check if a String Contains a Substring in Bash How to Convert a String to Lowercase in Bash

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How To Add Double Quotes Around Java Object And String Variable

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